Answer:
Jason is incorrect.
The caterpillar's rate is 2 ft/min
Step-by-step explanation:
The rate of motion is defined as the quotient between the distance covered (in our case 16 feet) divided by the time it took to cover that distance (in our case 8 minutes)
Then, the rate is:
[tex]rate=\frac{distance}{time} = \frac{16\,\,ft}{8\,\,min} = 2\,\frac{ft}{min}[/tex]
