Answer:
[tex]\frac{3}{8}[/tex]
Step-by-step explanation:
The computation of the fraction of her overall lawn remaining unmowed is shown below:
Let us assume that the back lawn be x
So the front lawn would be
[tex]= \frac{1}{3}\times x\\\\ = \frac{x}{3}[/tex]
So, the total lawn is ................... (i)
[tex]= x + \frac{x}{3}\\\\ = \frac{4x}{3}[/tex]
The back lawn mowed is [tex]\frac{2x}{3}[/tex]
Front lawn moved is [tex]\frac{x}{6}[/tex]
So, the total mowed is ....................(ii)
[tex]= \frac{2x}{3} + \frac{x}{6}\\\\ = \frac{5x}{6}[/tex]
So, the total unmowed is
[tex]= \frac{4x}{3} - \frac{5x}{6} \\\\= \frac{x}{2}[/tex]
Now the fraction is
[tex]= \frac{x}{2} \times \frac{3}{4x} \\\\ = \frac{3}{8}[/tex]
The fraction of the entire lawn unmoved is 3 / 8
The fraction is defined as the division of the whole part into an equal number of parts. The computation of the fraction of her overall lawn remaining unmowed is shown below:
Let us assume that the back lawn is x
So the front lawn would be
[tex]=\dfrac{1}{3}\times x[/tex]
[tex]=\dfrac{4x}{3}[/tex]
So, the total lawn is ................... (i)
[tex]=x+\dfrac{x}{3}[/tex]
The back lawn mowed is
The front lawn moved is
So, the total mowed is ....................(ii)
[tex]=\dfrac{2x}{3}+\dfrac{x}{6}[/tex]
[tex]=\dfrac{5x}{6}[/tex]
So, the total unmowed is
[tex]=\dfrac{4x}{3}-\dfrac{5x}{6}[/tex]
[tex]=\dfrac{x}{2}[/tex]
Now the fraction is
[tex]=\dfrac{x}{2}\times \dfrac{3}{4x}[/tex]
[tex]=\dfrac{3}{8}[/tex]
Therefore the fraction of the entire lawn unmoved is 3 / 8
To know more about fractions follow
https://brainly.com/question/78672
#SPJ5
