Answer:
Explanation:
No external force is acting on uranium nucleus so we can apply law of conservation of momentum . If M and m be the mass of bigger and smaller fragments respectively and V and v be their velocity after fission , Total momentum after fission = total momentum before fission
MV - mv = 0 , since the nucleus was at rest , its momentum before fission is zero . negative sign of mv is taken because smaller fragment will move in opposite direction to that of bigger fragment .
MV = mv
M / m = v / V
M > m
Hence,
v > V
So velocity of smaller fragment will be higher .
