Answer:
170 passenger . ( approx )
Explanation:
Total volume of metal making fuselage = π ( r₂² - r₁² ) l
r₂ is outer radius of cylindrical tube like fuselage
= 6.5 / 2 + .0025 = 3.2525 m
r₁ is inner radius of cylindrical tube like fuselage
= 6.5 / 2 = 3.25 m
l = 70.7 m
Total volume of fuselage = π ( r₂² - r₁² ) l
= 3.14 x 70.7 x ( 3.2525² - 3.25² )
= 221.998 ( 10.57875 - 10.5625)
= 3.60747 m³
If it is made of aluminium , its mass
= volume x density
= 3.60747 x 2700 kg
= 9740.16 kg
weight of passenger = 81 x 400 = 32400 kg
Total mass = 32400 + 9740.16
= 42140.16 kg
If it is made of iron , its mass
= volume x density
= 3.60747 x 7870 kg
= 28390.79 kg
If number of passenger required be n
81 n + 28390.79 = 42140.16 ( as per condition given )
n = 170 passenger . ( approx )