Answer:  Bearing = 41.41°
Step-by-step explanation:
[tex]\tan \theta=\dfrac{opposite}{adjacent}\\\\\\\tan \theta=\dfrac{240}{320}\\\\\\.\quad \theta=\tan^{-1}\bigg(\dfrac{240}{320}\bigg)\\\\\\.\quad \theta =48.59^o[/tex]
Bearing is measured clockwise from North (90° on a Unit Circle = bearing of 0°)
Bearing = 90° - Ф
       = 90° - 48.59°
       = 41.41°
