Please help me out!!!

Answer:
[tex]= 2^2^8 \times 3^-^2^0\times 9^4[/tex]
Step-by-step explanation:
[tex]\mathrm{Apply\:exponent\:rule}:\quad \left(a\times\:b\right)^n=a^nb^n\\\left(2^7\times\:3^{-5}\times\:9\right)^4=\left(2^7\right)^4\times\left(3^{-5}\right)^4\times\:9^4\\=\left(2^7\right)^4\cdot \left(3^{-5}\right)^4\cdot \:9^4\\\\= 2^2^8 \times 3^-^2^0\times 9^4[/tex]
Answer:
Multiply the exponent 4 by each of the exponents inside the parentheses.
Hope this helps..