What is the domain of this function(picture attached)? Due in 2 hours, 15 points and I'll give Brainliest!

Recall that you cannot take the square root of a negative. Thus, all values under the square root must be greater than or equal to 0. Thus, to find the domain, set the expression under the radical sign to greater than or equal to 0 and solve for x:

[tex](x-1)\geq 0[/tex]

Add 1 to both sides.

[tex](x-1)+1\geq 0+1\\x\geq 1[/tex]

Thus, the domain is:

[tex]x\geq 1[/tex]

All real numbers such that x is greater than or equal to 1.

09pqr4sT 09pqr4sT · Answer 2 · 2020-08-22T21:48:49+02:00

Answer:

[tex]\huge \boxed{x \geq 1}[/tex]

Step-by-step explanation:

The domain of a function is all possible values for x.

There are restrictions on the value of x.

The number in the square root has to be greater or equal to 0 to be defined. Since the square root of a number lesser than 0 will be undefined.

[tex]x-1\geq 0[/tex]

Adding 1 to both sides.

[tex]x-1+1 \geq 0+1[/tex]

[tex]x\geq 1[/tex]

The domain of the function is [tex]x\geq 1[/tex]

All real numbers greater or equal to 1.