Answer:
sin(B) = [tex]\frac{15}{17}[/tex]
cos(B) = [tex]\frac{8}{17}[/tex]
tan(B) = [tex]\frac{15}{8}[/tex]
Step-by-step explanation:
I always find it easiest to model out the triangle: Angle B will be at the converging point of a and c.
Using SOH CAH TOA, we know that the Sin of an angle will be its opposite over hypotenuse. The opposite is 15, and the hypotenuse is 17.
So [tex]\frac{15}{17}[/tex] is the sin of B.
We also know that the cosine of B will be it's adjacent over hypotenuse. The adjacent is 8 and the hypotenuse is 17, so
[tex]\frac{8}{17}[/tex]
Lastly, we know the tangent of B will be it's opposite over adjacent. The opposite of B is 15, and it's adjacent is 8, so
[tex]\frac{15}{8}[/tex] is the tangent of B.
Hope this helped!
