Respuesta :

Answer:

8

Step-by-step explanation:

Numbers divisible by 12 and 30:

  • 12= 2*6
  • 30= 5*6
  • LCM(12,30) = 2*5*6= 60

So, numbers should be divisible by 60

To find the greatest one divide 586 by 60 and take whole part of quotient, which is 9, so there are 9 multiples of 60 smaller than 586.

Excluding 60 which is less than 75.

So required number is 9 - 1 = 8.