Please Help! I'm Stuck!

Answer:
19
Step-by-step explanation:
Assuming that [tex]l[/tex] represents length and [tex]w[/tex] represents width, we can make a systems of equations and solve for l and w.
[tex]2l+2w=60[/tex], since the perimeter of a rectangle will be double the length plus double the width.
Also we can make the equation [tex]l = 2w+3[/tex], as stated in the last part of the question.
We can now substitute the value of [tex]2w+3[/tex] into the equation [tex]2l+2w=60[/tex] as l.
[tex]2(2w-3) + 2w = 60\\\\4w-6+2w=60\\\\6w-6=60\\\\6w=66\\\\w = 66\div6\\\\w = 11[/tex]
So we know the width is 11. Now that we know the width, we can substitute it back into the equation [tex]l = 2w+3[/tex] to find the length.
[tex]l=2\cdot11-3\\\\l=22-3\\\\l=19[/tex]
So the length is 19.
Hope this helped!