Jon was given a radical to simplify. His original problem had nothing already
simplified outside of the square root. His answer was 2xy^3z^4√3xz. What
must have been the original radical that Jon was given?

Respuesta :

Answer:

  [tex]\sqrt{12x^3y^6z^9}[/tex]

Step-by-step explanation:

  [tex]2xy^3z^4\sqrt{3xz}=\sqrt{(2xy^3z^4)^2(3xz)}=\sqrt{(2^2)(3)(x^2)(x)(y^6)(z^8)(z)}\\\\=\boxed{\sqrt{12x^3y^6z^9}}[/tex]

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The applicable rules of exponents are ...

  (a^b)^c = a^(bc)

  a√b = √(a^2·b)

  (a^b)(a^c) = a^(b+c)