Answer:
[tex]N=1.5N[/tex]
Explanation:
Hello,
In this case, since normality is defined in terms of the equivalent grams and the volume of the solution:
[tex]N=\frac{eq-g}{V}[/tex]
We need to compute the equivalent grams by considering that the molar mass of NaOH is 40 g/mol and one mole of NaOH contains one equivalent grams due to the presence of one hydroxyl ion only:
[tex]eq-g=30gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1eq-g}{1mol}=0.75eq-g[/tex]
And the volume in liters (0.500 L). Therefore, we obtain:
[tex]N=\frac{0.75eq-g}{0.500L} \\\\N=1.5N[/tex]
Regards.
