*see the given given in the attachment below
Answer:
x = 109°
Step-by-step Explanation:
Since AB is parallel to CF, m<BAE = m<AED = 38° (alternate interior angles are congruent)
Since AE = DE, ∆AED is an isosceles ∆.
The two base angles of any given isosceles ∆ are said to be congruent.
This means, m<EAD = m<EDA = ½(180 - m<AED)
m<EDA = [tex] \frac{1}{2}*(180 - 38) [/tex]
m<EDA = [tex] \frac{1}{2}*(142) = 71 [/tex]
x + m<EDA = 180° (angle on a straight line)
[tex] x + 71 = 180 [/tex]
[tex] x + 71 - 71 = 180 - 71 [/tex]
[tex] x = 109 [/tex]
Value of x = 109°
