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Turner’s treadmill starts with a velocity of −3.0 m/s and speeds up at regular intervals during a half-hour workout.After 33 min, the treadmill has a velocity of −6.7 m/s. What is the average acceleration of the treadmill during this period? Answer in units of m/s^2

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MathPhys

Explanation:

Acceleration is change in velocity over change in time.

a = Δv / Δt

a = (-6.8 m/s − (-3.0 m/s)) / (33 min × 60 s/min)

a = (-3.8 m/s) / (1980 s)

a = -0.0019 m/s²

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