Answer:
A
Step-by-step explanation:
So we have the two functions:
[tex]f(x)=x^2-1\\g(x)=\sqrt x[/tex]
And we want to find:
[tex](f\circ g)(1)[/tex]
This is the same as:
[tex]f(g(1))[/tex]
So, to find the answer, find g(1) first:
[tex]g(x)=\sqrt x\\g(1)=\sqrt1\\g(1)=1[/tex]
Now, substitute this value for g(1):
[tex]f(g(1))\\=f(1)[/tex]
And plug this into f(x):
[tex]f(x)=x^2-1\\f(1)=(1)^2-1\\f(1)=1-1=0[/tex]
Therefore:
[tex]f(1)=f(g(1))=(f\circ g)(1)=0[/tex]
Our answer is A
