Answer:
35°
Step-by-step explanation:
Produce BC in the direction of C which intersects DE at any point say P.
AB || ED... (given)
So, BP would be transversal.
[tex] \therefore m\angle DPB + m\angle FBP = 180\degree\\... (By\: interior \: \angle \: Postulate) \\
\therefore m\angle DPB + 125\degree = 180\degree\\
\therefore m\angle DPB = 180\degree - 125\degree \\
\huge \red {\boxed {\therefore m\angle DPB = 55\degree}} \\
m\angle DCP = 180\degree - 90\degree \\
m\angle DCP = 90\degree \\
x = 180\degree - (90\degree + 55\degree) \\
x = 180\degree - 145\degree \\
x = 35\degree [/tex]
