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Two forces 5N and 10N are acting at "O" and "P" respectively on a uniform rod of length 100 cm suspended at the position of center of gravity 50cm mark as shown in figure .​

Two forces 5N and 10N are acting at O and P respectively on a uniform rod of length 100 cm suspended at the position of center of gravity 50cm mark as shown in class=

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Eduard22sly

Answer:

Option C. 75 cm

Explanation:

To obtain the position of P, let us calculate the value of y as shown in the attached photo.

The value of y can be obtained as follow:

Anticlockwise moment = clockwise moment

Anticlockwise moment = 5 × 50

Anticlockwise moment = 250

Clockwise moment = y × 10

Anticlockwise moment = clockwise moment

250 = y × 10

Divide both side by 10

y = 250/10

y = 25 cm

Finally, we shall obtain the value of P as follow:

Since P lies after the pivot (i.e 50 cm), therefore,

P = 50 + y

y = 25

P = 50 + 25

P = 75 cm

Therefore, the position of P on the metre rod is 75 cm

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