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Janine completed 36 math problems. Craig completed 9 math problems. The number of problems that Janine completed is how many times the number of problems that Craig completed?

Respuesta :

musiclover10045

Divide the number Janine did by the number Craig did:

36/9 = 4

Janine did 4 times as many as Craig

Rileygrey245

Answer:

4 times

Step-by-step explanation:

Because 36 divided by 9 = 4

So your answer is 4 times the number of problems.