Answer:
[tex]f(x) = |2\cdot x^{2}+x|[/tex] and [tex]g(x) = x+1[/tex]
Step-by-step explanation:
Let [tex]f \circ g\, (x) = |2\cdot (x+1)^{2}+(x+1)|[/tex], a composition consist in replacing the variable of the first function ([tex]f(x)[/tex]) with the second function ([tex]g(x)[/tex]). By observation, it is quite evident that [tex]g(x) = x+1[/tex], whereas [tex]f(x) = |2\cdot x^{2}+x|[/tex].