Answer:
[tex]V=7.07L[/tex]
Explanation:
Hello,
In this case, for the statement:
"Calculate the volume in liters of a 0.133mol/L copper (II) sulfate solution that contains 150.g of copper (II) sulfate (CuSO4). Be sure your answer has the correct number of significant digits"
We initially have the molar concentration as well as the mass of the copper (II) sulfate, therefore, we must first compute the moles of the given compound considering its molar mass (159.54 g/mol):
[tex]n=150g*\frac{1mol}{159.54g}= 0.94mol[/tex]
Then, considering the definition of molar concentration or molarity, we compute the required volume as follows:
[tex]M=\frac{n}{V}\\ \\V=\frac{n}{M} =\frac{0.94mol}{0.133mol/L}\\ \\V=7.07L[/tex]
Best regards.
