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PLZZZ help asap will give the brain and 70 points!!!!! For 2x^2+5=-x, choose the correct substitution for a, b, and c in the standard form of ax^2+bx+c=0. A. a=2,b=1,c=5 B. a=2,b=1,c=-5 C. a=2,b=-1,c=5 D. a=2,b=5,c=-1

Respuesta :

adioabiola

Answer:

A. a=2, b=1, c=5

Step-by-step explanation:

Given:

2x^2+5=-x

Rearrange to have the format

ax^2+bx+c=0

2x^2+5=-x

Add x to both sides

2x^2 + 5 + x = - x + x

2x^2 + 5 + x = 0

2x^2 + x + 5 = 0

ax^2 + bx + c = 0

Where

a= coefficient of x ^2

b = coefficient of x

c= constant

Therefore,

a= 2

b = 1

c= 5

A. a=2,b=1,c=5 is the correct answer

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Answer:

[tex]\huge \boxed{\mathrm{A.} \ a=2, \ b=1, \ c=5}[/tex]

[tex]\rule[225]{225}{2}[/tex]

Step-by-step explanation:

2x² + 5 = -x

The quadratic equation is in the form :

ax² + bx + c = 0

Rewriting the equation by adding x to both sides :

2x² + 1x + 5 = 0

The value of a is 2.

The value of b is 1.

The value of c is 5.

[tex]\rule[225]{225}{2}[/tex]