Answer:
2.25V
Explanation:
In the above question, we are given an npn transistor.
It's VB = Biased voltage = 2.95V
We are asked to calculate the DC emitter voltage.
DC emitter voltage = VB - VBE
Where:
VBE = Voltage between the base and emitter of a bipolar junction transistor
VBE has a set standard voltage of 0.7V
Hence,
DC emitter voltage = 2.95V - 0.7V
= 2.25V
In this exercise we have to use the knowledge of voltage to calculate the difference, like this:
[tex]2.25V[/tex]
Knowing that the initial voltage is given by 2.95V and we want to find the voltage difference we have:
[tex]DC = VB - VBE[/tex]
Where, VBE = Voltage between the base and emitter of a bipolar junction transistor is equal to 0.7 V, this way:
[tex]DC = 2.95V - 0.7V = 2.25V[/tex]
See more about voltage at brainly.com/question/2364325
