Answer:
v = 2.89 m / s
Explanation:
This is a kinematics exercise, the centripetal acceleration is
a = v² / r
where a is the acceleration, v is the velocity and r the radius
let's clear
v = √a r
let's calculate
v = √ (27 0.31)
v = 2.89 m / s
this is the speed of the drum which is constant
The tangential speed of the rim will be "2.89 m/s".
Tangential speed seems to be the rate beyond which the item moving throughout a circle travels.
A wider radius indicates that perhaps the thing goes a considerable distance.
According to the question,
Radius, r = 0.31 m
Acceleration, a = 27 m/s²
We know,
→ [tex]a = \frac{v^2}{r}[/tex]
or,
→ [tex]v= \sqrt{ar}[/tex]
By substituting the values,
[tex]= \sqrt{27\times 0.31}[/tex]
[tex]= 2.89 \ m/s[/tex]
Thus the answer above is right.
Find out more information about the tangential speed here:
https://brainly.com/question/10493657
