Respuesta :
Answer:
The age of brothers are 4 years and 2 years respectively.
Step-by-step explanation:
We are given that the ages of two brothers have a ratio of 2 to 1. When 4 years have passed, the ratio of their ages will be 8 to 6.
Let the age of the first brother be 'x years' and the age of the second brother be 'y years'.
So, according to the question;
- The first condition states that the ages of two brothers have a ratio of 2 to 1, that means;
[tex]\frac{x}{y} =\frac{2}{1}[/tex]
[tex]x=2y[/tex] -------------- [equation 1]
- The second condition states that when 4 years have passed, the ratio of their ages will be 8 to 6, that means;
[tex]\frac{x+4}{y+4}=\frac{8}{6}[/tex]
[tex]6({x+4})=8}(y+4)[/tex]
[tex]6x+24=8y+32[/tex]
[tex]6(2y)+24=8y+32[/tex]
[tex]12y-8y=32-24[/tex]
[tex]4y=8[/tex]
[tex]y=\frac{8}{4}[/tex] = 2 years
Putting the value of y in equation 1 we get;
x = 2y
x = [tex]2 \times 2[/tex] = 4 years
Hence, the age of brothers are 4 years and 2 years respectively.
