Answer:
1.43 × 10^-2 m/s
Explanation:
Given the following :
Distance covered away from it's master = D1 = 24×10^-2 m
Time taken to cover the distance = t1 = 12.6s
Then runs halfway back D2 =
D1/ 2 = (24× 10^-2m) / 2 = 12 ×10^-2m
Time taken =T2 = T1/3 = 12.6/3 = 4.2s
Since the kitten ran in a straight line, the it is linear :
Average speed
Linear Average Velocity:
Change in distance / change in time
(D1 - D2) / (T2 - T1)
(24 - 12)×10^-2 / (12.6 - 4.2)
(12 × 10^-2)m / 8.4s
1.4285 × 10^-2
= 1.43 × 10^-2m/s
