Respuesta :
Answer:
to two decimal places
= 6.04 mega joules
Step-by-step explanation:
The volume of the half tank
= πr²h
r= 2 m
h= 14/2= 7 m
Volume= 22/7 *2² *7
Volume= 88 m³
work (in mega-joules) needed to pump all of the water to the top of the tank
= Volume*mass density *acceleration*distance
= 88*1000*9.8*7
= 6036800 joules
In mega joules
= 6.036800 mega Joules
to two decimal places
= 6.04 mega joules
The work needed to pump all of the water to the top of the tank is 6.03 MJ
What is work?
Work is said to be done whenever a force move a body through a certain distance.
To calculate the work needed to pump the water to the tank, first we need to find the volume of the water in the tank half full.
Formula:
- V = πr²h/2................ Equation 1
Where:
- V = Volume of half full water in the tank
- h = height of the tank
- r = radius of the base of the tank
- π = pie
From the question,
Given:
- r = 2 m
- h = 14 m
- π = 3.14
Substitute these values into equation 1
- V = 3.14(2²)(14)/2
- V = 87.92 m³.
Finally, to get the work needed to pump all the water to the top of the tank, we use the formula below.
- W = ρVhg/2................. Equation 2
Where:
- W = Work needed to pump all the water to the of the tank
- ρ = Density of the tank
- h = height of the tank
- V = Volume of halfull water in the tank
- g = acceleration due to gravity
From the question.
Given:
- ρ = 1000 kg/m³
- h = 14
- g = 9.8 m/s²
- V = 87.92 m³
Substitute these values into equation 2
- W = 1000(14)(9.8)(87.92)/2
- W = 6031312 J
- W = 6.03 MJ.
Hence, The work needed to pump all of the water to the top of the tank is 6.03 MJ.
Learn more about work here: https://brainly.com/question/8119756
