Answer:
[tex] \boxed{\sf Acceleration \ (a) = 5.7 \ m/s^2} [/tex]
Given:
Initial velocity (u) = 10 m/s
Final velocity (v) = 30 m/s
Time taken (t) = 3.5 seconds
To Find:
Acceleration (a) of the car
Explanation:
From equation of motion:
[tex] \boxed{ \bold{ v = u + at}}[/tex]
Substituting value of v, u & t in the equation:
[tex] \sf \implies 30 = 10 + a(3.5) \\ \\ \sf \implies 30 - 10 = 3.5a \\ \\ \sf \implies 20 = 3.5a \\ \\ \sf \implies 3.5a = 20 \\ \\ \sf \implies a = \frac{20}{3.5} \\ \\ \sf \implies a = 5.7 \: m/s^2[/tex]
[tex] \therefore[/tex]
Acceleration (a) of the car = 5.7 m/s²
