A student has scores of 85,83,98 and 77 on four quizzes. What must she score on the fifth quiz to have an average of at least 84?

We need to find the solution to:
(85 + 83 + 98 + 77 + x) / 5 >= 84 where x is the score in the last test
This is the same as:
(343 + x) / 5 >= 84
Multiplying both sides by 5 we get
343 + x >= 420
Subtracting 343 from both sides we get
x >= 77

There for the student must get a score of at least 77 on the last tests.

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AmitPaswan AmitPaswan · Answer 2 · 2022-06-28T17:40:54+02:00

She should score more than 77 on the fifth quiz to have an average of at least 84 .

What is average?

The average is the middle value of a set of numbers. This isn't to be confused with the median, which is the middle of a set of numbers. The average is the middle value of the numbers. If you need to find the average of a set of numbers, you add them all together and divide by the amount of numbers.

Formula of average:

[tex]Average = \frac{Sum of terms }{Number of terms }[/tex]

According to the question

A student has scores on four quizzes : 85,83,98,77

she score on the fifth quiz to have an average of at least 84

Let fifth quiz score = x

By using formula of average:

[tex]Average = \frac{Sum of terms }{Number of terms }[/tex]

As average should be at least 84

[tex]84 < \frac{85+83+98+77+x }{5 }[/tex]

420 < 343+x

420 - 343 < x

77< x

Therefore,

x should be greater than 77 .

Hence, she should score more than 77 on the fifth quiz to have an average of at least 84 .

To know more about average here:

https://brainly.com/question/24057012

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