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Write the quadratic equation in standard form and then choose the value of "b."
(2x - 1)(x + 5) = 0
O
10
011
pllllllls help me

Respuesta :

r3t40

[tex](2x-1)(x+5)=2x^2+9x-5=0[/tex].

The quadratic equation has a general form of

[tex]ax^2+bx+c=0[/tex].

So your "b" is 9.

Hope this helps.

nermay7

Answer:  Answer is in the steps

Step-by-step explanation:

(2x-1)(x+5) = 0    First expand the left side by apply the distributive property twice.

(2x -1)(x+5) =0  

x(2x -1) =  2x^2 -1x  

5(2x -1) =  10x -5  

Now rewrite them all together

2x^2 - 1x +10x -5  = 0   combine like terms on the left side.

[tex]2x^{2}[/tex] + 9x -5 = 0      a is the first leading coefficient,b is the second leading coefficient, and  c is the constant.

So in this case, the value of b is 9.

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