Answer:
If you meant the area was 255 in²:
Perimeter is [tex]4\sqrt{255}[/tex], or around 63.89 in.
If you meant that the area was 225 in²:
Perimeter is 60 in
Step-by-step explanation:
If you meant the area was 255 in²:
If we have a square with an area of 255 in², then it's side length will be [tex]\sqrt{255}[/tex] inches long, since the area of a square is [tex]l^2[/tex], where l is the length.
Since [tex]\sqrt{255}[/tex] doesn't return a rational number, we'll leave it as [tex]\sqrt{255}[/tex].
Now that we know the side length, the perimeter of a square is represented as [tex]4l[/tex], where l is the length.
We know the length is [tex]\sqrt{255}[/tex], so we can multiply this by 4.
[tex]4\sqrt{255}[/tex]. This is the simplest it gets.
If you meant the area was 225 in²:
Following the same concept as again:
Length: [tex]\sqrt{225} = 15[/tex]
Perimeter: [tex]4\cdot15=60[/tex] in
Hope this helped!
