The balanced chemical equation is :
[tex]2CO_2->2CO+O_2\\\\[/tex]
Moles of [tex]CO_2[/tex] ,
[tex]n = \dfrac{100\ g}{44.01\ g/mol}\\\\n=2.27\ mol[/tex]
Now, by given chemical equation , we can see 2 mole of [tex]CO_2[/tex] react with 1 mole of [tex]O_2[/tex].
So , 2.27 mole react with :
[tex]N=\dfrac{2.27}{2}\ mol\\\\N=1.135\ mol[/tex]
Mass of oxygen is :
[tex]M = N \times 16\\\\M=1.135\times 16\ g\\\\M =18.16\ g[/tex]
Therefore, mass of oxygen in grams produced is 18.16 g.
Hence, this is the required solution.
