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The temperature of a sample of water from the faucet increases from 22.7°C to 48.9°C when 3,710J are applied through electric shock. What is the mass of the sample of water? *DO NOT put units in your answer.**
Please help guys

Respuesta :

sebassandin

Answer:

33.8.

Explanation:

Hello,

In this case, since the used equation is:

[tex]Q=mCp(T_2-T_1)[/tex]

Whereas the specific heat is 4.184 J/(g°C), we compute the mass as follows:

[tex]m=\frac{Q}{Cp(T_2-T_1)}[/tex]

Thus, the mass turns out:

[tex]m=\frac{3,710J}{4.184\frac{J}{g\°C} (48.9-22.7)\°C}\\\\m=33.8g[/tex]

And without units:

33.8.

Best regards.

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