Respuesta :

CintiaSalazar

Answer:

A 100-watt light bulb takes 100 seconds to use 10,000 J of electrical energy.

Explanation:

Power refers to the amount of work done (or energy consumed) per unit of time. It is usually measured in watts (W), which is equal to 1 Joules per second ([tex]\frac{J}{s}[/tex])

So, by definition, to calculate the power consumed or supplied in a time interval the following expression is used:

[tex]P=\frac{W}{t}[/tex]

where P is the power measured in Watts, W is the work measured in Joules, and t is the time measured in seconds.

In this case:

  • P=100 Watt
  • W= 10,000 J
  • t= ?

Replacing:

[tex]100 Watt=\frac{10,000 J}{t}[/tex]

Solving:

[tex]t=\frac{10,000 J}{100 Watt}[/tex]

t=100 seconds

A 100-watt light bulb takes 100 seconds to use 10,000 J of electrical energy.

Cricetus

The time taken by a 100 watt light bulb to use 10,000 J of electrical energy will be:

"100 seconds".

Electrical energy

According to the question,

Power, P = 100 Watt

Work done, W = 10000 J

We know the relation,

→ Power (P) = [tex]\frac{Work \ done (W)}{Time (t)}[/tex]

or,

The time taken will be:

→ t = [tex]\frac{W}{P}[/tex]

By substituting the above values, we get

    = [tex]\frac{10000}{100}[/tex]

    = 100 seconds

Thus the approach above is appropriate.

Find out more information about electrical energy here:

https://brainly.com/question/13280097

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