Answer:
(1) the total momentum is 275 kgm/s
(2) The momentum of each ball changes, and the total momentum stays the same.
(3) The mass of the second object is 3.5 kg
Explanation:
(1) In a closed system the total momentum is constant, it never changes.
For the given momentums, the total momentum is given as;
Total momentum = 110 kgm/s + 65 kgm/s + 100 kgm/s = 275 kgm/s
(2) Given;
Initial momentum of the ball at rest, P = mv
where;
m is mass of the ball = 1 kg
v is velocity of the ball = 0 (at rest)
P = 1 x 0 = 0
Initial momentum of the ball in motion = 24 kgm/s
The total momentum of the system = 0 + 24 kgm/s = 24 kgm/s
Thus, the total momentum of the system remains the same while the momentum of each ball changes after collision, because the ball at rest had zero momentum at initial but changed to 24kgm/s after collision.
The momentum of each ball changes, and the total momentum stays the same.
3.
mass of first object m₁ = 1.5 kg
common velocity of both objects after collision, v = 50 m/s
total momentum of the system, P = 250 kgm/s
let the mass of the second object = m₂
v(m₁ + m₂) = P
v(m₁ + m₂) = 250
50(1.5 + m₂) = 250
1.5 + m₂ = 250 / 50
1.5 + m₂ = 5
m₂ = 5 - 1.5
m₂ = 3.5 kg
