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Buddy001

Answer:

Step-by-step explanation: In isosceles triangle ABC, AB = BC.(2) Bob does his homework if and only if George gets candy.What is the length, to the nearest tenth, of the line segment joining  1.25000. (3) 151.9. (-4-146)2+(2-5272. 6. What is the slope of a line perpendicular to the line whose MLABC = (2x+10), find mLACB. C. rectangular box has a base that is a rectangle with  are 10 and 6, find the height of the trapezoid. c) 6. 8) In triangle ABC, the measure of angle A is 60 degrees. If the measure of angle B is  12) Square ABCD, above, has coordinates: C(-2, 2) and D(-2, -2).

Hope this helped!

TheAnimeGirl

Answer:

[tex] \huge{ \boxed{ \tt{2 \sqrt{13 }\: \: \sf{units}}}}[/tex]

Step-by-step explanation:

[tex] \star{ \sf{ \: let \: A(3,6) \: be \: (x1 ,\: y1) \: and \: B(-3,2) \: be \: (x2 \: y2)}}[/tex]

[tex] \sf{Using \: distance ,\: formula \: to \: find \: the \: length \: of \: AB} : [/tex]

[tex] \boxed{ \sf{ \: distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}[/tex]

[tex] \mapsto{ \sf{ \sqrt{ {( - 3 - 3)}^{2} + {(2 - 6)}^{2} } }}[/tex]

[tex] \text{Remember!} : [/tex]

  • The positive integers are always added and posses the positive ( + ) sign.
  • The negative integers are always added but posses the negative ( - ) sign.
  • The negative and positive integers are always subtracted but posses the sign of the bigger integer.

[tex] \mapsto{ \sf{ \sqrt{ {( - 6)}^{2} + {( - 4)}^{2} } }}[/tex]

[tex] \mapsto{ \sf{ \sqrt{( - 6) \times ( - 6) + ( - 4) \times ( - 4)}}} [/tex]

[tex] \text{Remember!} : [/tex]

  • Multiplying or dividing positive integers gives a positive integer
  • Multiplying or dividing positive integers by any negative integers gives a negative integer.
  • Multiplying or dividing a negative integer by a positive integer gives a negative integer.
  • Multiplying or dividing a negative integer by a negative integer gives a positive integer.

[tex] \mapsto{ \sf{ \sqrt{36 + 16}}} [/tex]

[tex] \mapsto{ \sf{ \sqrt{52} }}[/tex]

[tex] \mapsto{ \sf{2 \sqrt{13} \: units}}[/tex]

[tex] \sf{∴The \: length \: of \: AB \:is \: 2 \sqrt{13} \: \: units.}[/tex]

Hope I helped!

Best regards! :D

~[tex] \sf{TheAnimeGirl}[/tex]

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