Rewrite
[tex]2x {}^{2} + 2y {}^{2} - 8x + 10y + 2 = 0[/tex]
in standard form find the center and radius of the circle.show all of your work for full credit​

Respuesta :

Answer:

first group x's with x's and y's with y's

then complete the squra with x's and y's

2x^2-8x+2y^2+10y+2=0

2(x^2-4x)+2(y^2+5y)+2=0

take 1/2 of linear coeficient and square

-4/2=-2, (-2)^2=4

5/2=2.5, 2.5^2=6.25

add that and negative inside

2(x^2-4x+4-4)+2(y^2+5y+6.25-6.25)+2=0

factor perfect squares

2((x-2)^2-4)+2((y+2.5)^2-6.25)+2=0

distribute

2(x-2)^2-8+2(y+2.5)^2-12.5+2=0

2(x-2)^2+2(y+2.5)^2-18.5=0

add 18.5 both sides

2(x-2)^2+2(y+2.5)^2=18.5

divide both sides by 2

(x-2)^2+(y+2.5)^2=9.25

that is a circle center (2,-2.5) with radius √9.25