Answer:
[tex]r_{Br_2}=2.1x10^{-4}M/s[/tex]
Explanation:
Hello,
In this case, for the reaction:
[tex]5Br^-(aq)+BrO_3^-(aq)+6H^+(aq)\rightarrow 3Br_2(aq)+3H_2O(l)[/tex]
Thus, via the rate proportions between Brā» and Brā for which the stoichiometric coefficients are 5 and 3 respectively, we can write:
[tex]\frac{r_{Br^-}}{-5} =\frac{r_{Br_2}}{3}[/tex]
Hence, the rate of appearance of Brā turns out:
[tex]r_{Br_2}=\frac{3r_{Br^-}}{-5}=\frac{3*-3.5x10^{-4}M/s}{-5}\\ \\r_{Br_2}=2.1x10^{-4}M/s[/tex]
Take into account that the rate of disappearance is negative for reactants.
Best regards.