Answer:
[tex]r>6[/tex]
Step-by-step explanation:
So we have the inequality:
[tex]5(6+3r)+7>127[/tex]
First, let's subtract 7 from both sides:
[tex](5(6+3r)+7)-7>(127)-7[/tex]
The left side cancels:
[tex]5(6+3r)>127-7[/tex]
Subtract on the right:
[tex]5(6+3r)>120[/tex]
Now, let's divide both sides by 5:
[tex]\frac{5(6+3r)}{5}>\frac{120}{5}[/tex]
The left side cancels. Divide on the right:
[tex]6+3r>24[/tex]
Subtract 6 from both sides:
[tex](6+3r)-6>(24)-6[/tex]
The left side cancels. Subtract on the right:
[tex]3r>18[/tex]
Divide both sides by 3:
[tex]\frac{3r}{3}>\frac{18}{3}[/tex]
Divide:
[tex]r>6[/tex]
So, our answer is all values greater than 6.
And we're done!
