Complete question
The complete question is shown on the first uploaded image
Answer:
The value is [tex]C = 0.02009 \ M [/tex]
Explanation:
From the question we are told that
The mass of NaOH is [tex]m= 0.8036 g[/tex]
In the question DI (stands for de-ionized water )
So the number of moles of NaOH present in the given mass is
[tex]n = \frac{m}{Z}[/tex]
Here Z is the molar mass of NaOH with value [tex]Z = 40 \ g/ mol[/tex]
So
[tex]n = \frac{0.8036}{40}[/tex]
[tex]n =0.02009 \ mols [/tex]
Given that the volume of the flask is V = 1 L then we can evaluated the concentration as
[tex]C = \frac{n}{V}[/tex]
=> [tex]C = \frac{0.02009}{1}[/tex]
=> [tex]C = 0.02009 \ M [/tex]
