Respuesta :
Answer:
The solar panel produce 6.48 × 10⁶ J of energy each day.
Step-by-step explanation:
If the solar cells were 100% efficient and generate 1000 watts of power per square meter
The power generated per square meter will be
[tex]\frac{100}{100} \times 1000 watts/m^{2}[/tex]
= 1000 watts/m²
This is the power that would be generated per square meter if the solar cells were 100% efficient.
Now, for a 1 square meter panel of solar cells with an efficiency of 30%, the power generated will be
[tex]\frac{30}{100} \times 1000 watts/m^{2} \times 1m^{2}[/tex]
= 300 watts
This is the power that would be generated by a 1 square meter panel of solar cells with an efficiency of 30%
Now, to determine the energy in joules (J) that the solar panel produce each day
We can determine the energy from the formula
Energy = Power × time
From the question, the solar cells receives the equivalent of 6 hours of direct sunlight per day, that is
Time = (6 × 60 × 60) secs = 21600 secs
Hence,
Energy = 300 watts × 21600 secs
Energy = 6480000 Joules
Energy = 6.48 × 10⁶ J
Answer:
The value is [tex]E = 6480000 J/day [/tex]
Step-by-step explanation:
The power produced per square meter is [tex]P = 1000 \ W[/tex]
The efficiency of a solar cell is [tex]\eta = 100\%[/tex]
The efficiency of 1 square meter panel of solar cells is [tex]\eta_b = 30\%[/tex]
The duration of sunlight received by a one square meter panel of solar cells is t = 6 * 60 *60 = 21600 seconds
Generally the power generated by 1 square meter panel of solar cells is mathematically represented
[tex]P_a = \eta_b * P[/tex]
[tex]P_a = 0.3 * 1000[/tex]
[tex]P_a = 300[/tex]
Generally the Energy produced by 1 square meter panel of solar cells per day is mathematically represented as
[tex]E = P_a * t[/tex]
=> [tex]E = 300 * 21600 [/tex]
=> [tex]E = 6480000 J/day [/tex]
