Answer:
The value is [tex]x =104.63 \ mL [/tex]
Explanation:
From the question we are told that
The concentration of NaOH is [tex]C = 0.595\ M[/tex]
The mass of glyceryl tristearate is [tex]m = 18.5 \ g[/tex]
The reaction of tristearate (tristearin) with NaOH is shown on the first uploaded image (Reference Wikidot)
From the reaction we see that 1 mole of tristearate (tristearin) (with molar mass Z_b = 891.5 g/mol ) reacted with 3 moles of NaOH (with molar mass Z_a = 40 g/mol)
So the mass of tristearate (tristearin) in the equation is (m_k = 1 *891.5 = 891.5g )
and
The mass of NaOH in the equation is (m_x = 3 * 40 = 120 g )
Generally the mass of NaOH that will react with [tex]m = 18.5 \ g[/tex] of glyceryl tristearate is mathematically represented as
[tex]h = \frac{18.5 * 120}{891.5}[/tex]
=> [tex]h = 2.490 \ g [/tex]
The mass of NaOH in 0.595 M ( mol/L) (i.e 0.595 mol in L(1000 mL) )of NaOH solution is mathematically evaluated as
[tex]w = Z_a * C[/tex]
=> [tex]w = 40 * 0.595[/tex]
=> [tex]w = 23.8 \ g [/tex]
So if
[tex]w = 23.8 \ g [/tex] is in 1000mL of the given solution of NaOH
[tex]h = 2.490 \ g [/tex] will be is x mL of the NaOH solution
So
[tex]x = \frac{2.490 * 1000 }{23.8}[/tex]
[tex]x =104.63 \ mL [/tex]
