Respuesta :
List all prime factors for each number.
Prime Factorization of 10 is:
2 x 5 => 21 x 51
Prime Factorization of 13 shows:
13 is prime => 131
Prime Factorization of 40 is:
2 x 2 x 2 x 5 => 23 x 51
For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.
The new superset list is
2, 2, 2, 5, 13
Multiply these factors together to find the LCM.
LCM = 2 x 2 x 2 x 5 x 13 = 520
In exponential form:
LCM = 23 x 51 x 131 = 520
LCM = 520
Therefore,
LCM(10, 13, 40) = 520
Prime Factorization of 10 is:
2 x 5 => 21 x 51
Prime Factorization of 13 shows:
13 is prime => 131
Prime Factorization of 40 is:
2 x 2 x 2 x 5 => 23 x 51
For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.
The new superset list is
2, 2, 2, 5, 13
Multiply these factors together to find the LCM.
LCM = 2 x 2 x 2 x 5 x 13 = 520
In exponential form:
LCM = 23 x 51 x 131 = 520
LCM = 520
Therefore,
LCM(10, 13, 40) = 520
Answer:
520
Step-by-step explanation:
The least common multiple of 13, 10 and 40 is the smallest positive integer that divides the numbers 13, 10 and 40 without a remainder.
That would 520 because it could be divided into 13, 10 and 40 without a remainder.
520 divided by 10= 52
520 divided by 13= 40
520 divided by 40= 13