contestada

In bungee jumping, a bungee jump is the amount the cord will stretch at the bottom of the fall. The stiffness of the cord is related to the amount of stretch by the equation given below. K = [(2W(S+L)]/(S^2) W= weight K = cord stiffness (pounds per foot) L = free length of cord (feet) S = stretch (feet) (a) A 190-pound person plans to jump off a ledge attached to a cord of length 52 feet. If the stiffness of the cord is no less than 28 pounds per foot, how much will the cord stretch?

Respuesta :

hellohibye0123

Answer:

6.7ft

Step-by-step explanation:

190÷28=6.7 is correct

abidemiokin

If the stiffness of the cord is no less than 28 pounds per foot, the cord stretch will be approximately 7 feet long

Given the equation that related the stiffness of the cord is expressed as:

[tex]K=\frac{(2W(S+L))}{S^2}[/tex] where:

W is the weight

K = cord stiffness (pounds per foot)

L = free length of cord (feet)

S = stretch (feet)

Given the following parameters

W = 190 pounds

L = 52 feet

k = 28 pounds per foot

Required

Stretch S

Substitute the given expressions into the equation above to have:

[tex]28=\frac{(2(190)(S+52))}{S^2}\\28S^2=380(S+52)\\28S^2 = 380S+19,760\\28S^2 - 380S-19,760=0\\[/tex]

On factorizing the result

The stretch is approximately 7 feet long

Learn more here: https://brainly.com/question/21406377

Otras preguntas