Answer:
[tex]Sn_2O[/tex]
Explanation:
Hello,
In this case, given that the mass of the product is 0.534 g, we can infer that the percent composition of tin is:
[tex]\%Sn=\frac{0.500g}{0.534g}*100\%\\ \\\%Sn=93.6\%[/tex]
Therefore, the percent composition of oxygen is 6.4% for a 100% in total. Thus, with such percents we compute the moles of each element in the oxide:
[tex]n_{Sn}=93.6gSn*\frac{1molSn}{118.8gSn} =0.788molSn\\\\n_O=6.4gO*\frac{1molO}{16gO}=0.4molO[/tex]
In such a way, for finding the smallest whole number we divide the moles of both tin and oxygen by the moles of oxygen as the smallest moles:
[tex]Sn:\frac{0.788}{0.4}=2\\ \\O:\frac{0.4}{0.4}=1[/tex]
Therefore, the empirical formula is:
[tex]Sn_2O[/tex]
Best regards.
