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The graph shows the distribution of weights (in pounds) of male duck-billed platypuses. The distribution is approximately Normal, with a mean of 3.75 pounds and a standard deviation of 0.52 pounds. What percent of male duck-billed platypuses have a weight of between 2.71 and 4.79 pounds?

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Answer:

Choice B) The distribution is approximately Normal, with a mean of 3.75 pounds and a standard deviation of 0.52 pounds.

Step-by-step explanation:

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Using the normal distribution principle, the percentage with weight between 2.71 and 4.79 is 95.45%

Using the Zscore relation :

  • Zscore = (X - μ) ÷ σ

For X = 2.71 :

Zscore = (2.71 - 3.75) ÷ 0.52 = - 2

Using a normal distribution table :

P(Z < - 2) = 0.02275

For X = 4.79 :

Zscore = (4.79 - 3.75) ÷ 0.52 = 2

Using a normal distribution table :

P(Z < 2) = 0.97725

P(Z < 2) - P(Z < - 2) = 0.97725 - 0.02275 = 0.9545

Therefore, the required percentage is 95.45%

Learn more : https://brainly.com/question/15139545

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