Answer:
5m/s
Explanation:
If you do 90-40 (the two distances the problem gave) which will give you 50 meters, and then 15-5 (the two times given) which will give you 10. All you do after that is divide your new found distance with your new time 50/10 and boom chicken soup you got your final answer of 5 m/s :)
We have that The cars displacement is
d=50m
The magnitude of the average velocity is
Avg V=2.5m/s
From the question we are told
A car travels 90 meters due North in 15 seconds. The car turns around and travels 40 meters due south in 5 seconds. What is the magnitude of the average velocity of the car during this 20-second interval
Generally the equation for the Total displacement is mathematically given as
d=initial displacement -final displacement
Therefore
d=90-40
d=50m
Generally the equation for the average velocity is mathematically given as
[tex]Avg V=\frac{m}{s}\\\\Avg V=\frac{50}{20}[/tex]
Avg V=2.5m/s
Therefore
The cars displacement is
d=50m
The magnitude of the average velocity
Avg V=2.5m/s
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