Your answer should be in the form p(x)+\dfrac{k}{x-1}p(x)+
x−1
k

p, left parenthesis, x, right parenthesis, plus, start fraction, k, divided by, x, minus, 1, end fraction where ppp is a polynomial and kkk is an integer.
\dfrac{x^2+2}{x-1}=
x−1
x
2
+2

Respuesta :

Answer:

Step-by-step explanation:

the answer i got was -57

Functions can be rewritten is several forms.

The new form of the function is: [tex]\mathbf{f(x) = \frac{x^2}{x - 1} + \frac{2}{x-1}}[/tex]

The function is given as:

[tex]\mathbf{f(x) = \dfrac{x^2+2}{x-1}}[/tex]

Split

[tex]\mathbf{f(x) = \frac{x^2}{x - 1} + \frac{2}{x-1}}[/tex]

The form is given as:

[tex]\mathbf{f(x) = p(x) + \frac{k}{x - 1}}[/tex]

So, by comparison

[tex]\mathbf{p(x) = \frac{x^2}{x - 1}}[/tex]

[tex]\mathbf{k =2}[/tex]

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