Answer:
a) Density of unknown liquid = 0.934 g/cm³
b) Yes
c) The unknown liquid is methyl acetate
Note: The question is missing some parts; the densities of the liquids from the material data sheet. A similar question is given below:
A chemist working as a safety inspector finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet says the cabinet is used to store bottles of acetone, chloroform, methyl acetate, glycerol, and ethanolamine.
The chemist plans to try to identify the unknown liquid by measuring the density and comparing to known densities. First, from his collection of Material Safety Data Sheets (MSDS), the chemist finds the following information: (the attachment below shows a table of the Material Safety Data Sheet)
Explanation:
Part 1
Density = mass/volume
Mass of unknown liquid = 512.0 g
Volume of unknown liquid = 0.548 L = 548 cm³ (Note: 1 L = 1000 cm³)
Density = 512.0 g/548 cm³ = 0.934 gcm³l to 3 significant figures.
Part 2
Yes, it is possible to identify the liquid from the value of its calculated density when compared with that of the known liquids in the Materials and Safety Data Sheet.
Part 3
The unknown liquid is methyl acetate since the density of the unknown liquid matches its density.
