Ohms's law of electricity states that V=IR, where V is voltage, I the current, and R represents the resistance.

A(1).Rewrite The Equation to isolate I

B(2).If V=220 volts and R= ohms, what is the value for I?_____amperes.

C(3). Rewrite the equation to isolate R.

D(4).If V=550 and I=1.5 amperes, what is the value of R?_____ohms.

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Answer:

1)

[tex] i = \frac{v}{r} [/tex]

2)no ohms

3)

[tex]r = \frac{v}{i} [/tex]

4)

[tex] \frac{550}{1.5} = r \\ \\ r = 366.66 [/tex]

A(1). The Equation to isolate I will be I = V / R.

B(2).If V=220 volts and R= 2 ohms, what is the value for I will be 110 amperes

C(3). The equation to isolate R will be R = V / I.

D(4).If V=550 and I=1.5 amperes, what is the value of R will be 366.66 Ohms.

What is Ohm's law?

Ohms's law of electricity states that the current passing through the closed circuit is directly proportional to the voltage developed across the circuit.

Where R is the constant and called the resistance. The resistance is actually the restriction offered by the material in the flow of the charge or current.

The mathematical form of Ohm's law is given as:-

V=IR,

where V is voltage, I is current, and R represents the resistance.

A). The Equation to isolate I will be,

I = V / R.

B). If V=220 volts and R= 2 ohms, what is the value I will be

I = V / R

I = 220 / 2 =110 Volts.

C). The equation to isolate R will be,

R = V / I.

D). If V=550 and I=1.5 amperes, what is the value of R will be,

R = V / I

R = 550 / 1.5 = 366.66 Ohms.

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