Answer:
The answer is "[tex]\bold{x^2 + 2x - 8< 0}[/tex]"
Step-by-step explanation:
In this question, we calculates the roots value after compare with 0.
In the first point:
[tex]\to \bold{x^2 - 2x - 8 < 0}[/tex]
[tex]x^2 - (4-2)x - 8 < 0\\\\x^2 - 4x +2x - 8 < 0\\\\x(x - 4) +2(x - 4) < 0\\\\ \ \ \ (x - 4)(x + 2) < 0[/tex]
In the second point:
[tex]\to \bold{x^2 + 2x - 8 < 0}[/tex]
[tex]x^2 + (4-2)x - 8 < 0\\\\x^2 +4x -2x - 8 < 0\\\\x(x + 4) -2(x +4) < 0\\\\ \ \ \ (x + 4)(x - 2) < 0\\[/tex]
In the third point:
[tex]\to \bold{x^2 - 2x - 8 > 0}[/tex]
[tex]x^2 -(4-2)x - 8 < 0\\\\x^2 -4x +2x - 8 < 0\\\\x(x - 4) +2(x -4) < 0\\\\ \ \ \ (x - 4)(x + 2) < 0\\[/tex]
In the fourth point:
[tex]\to \bold {x^2 + 2x - 8 > 0}[/tex]
[tex]x^2 +(4-2)x - 8 < 0\\\\x^2 +4x -2x - 8 < 0\\\\x(x + 4) -2(x +4) < 0\\\\ \ \ \ (x + 4)(x - 2) < 0\\[/tex]
As there are roots -4 and 2, whether choice B and D is the answer. when measuring a point within the interval from -4 to 2, it is negative, that's why second choice is correct.
Answer:
the answer is B on edge good luck
Step-by-step explanation:
lol
